梳理Immutable常用API

Immutable.fromJS({
  a: {
    b: [1, 2, 3],
    c: 40
  }
});
// 得到
Map {
  "a": Map {
    "b": List [1, 2, 3],
    "c": 40
  }
}

// 常见
const t1 = Immutable.fromJS({a: {b: [10, 20, 30]}, c: 40});
console.log(t1);

// 不常用
const t2 = Immutable.fromJS({a: {b: [10, 20, 30]}, c: 40}, function(key, value) {
    // 定制转换方式，下这种就是将Array转换为List，Object转换为Map
    const isIndexed = Immutable.Iterable.isIndexed(value);
    return isIndexed ? value.toList() : value.toOrderedMap();
    // true, "b", {b: [10, 20, 30]}
    // false, "a", {a: {b: [10, 20, 30]}, c: 40}
    // false, "", {"": {a: {b: [10, 20, 30]}, c: 40}}
});
console.log(t2);

import { Map, is } from 'immutable'
const map1 = Map({ a: 1, b: 1, c: 1 })
const map2 = Map({ a: 1, b: 1, c: 1 })

map1 === map2   //false

Object.is(map1, map2) // false

is(map1, map2) //  true 只检测值是否相等

// list
console.log(List([1,2,3,4]).size);// 4
console.log(List.of(1, 2, 3, 4).size);// 4

// map
console.log(Map({key: "value2", key1: "value1"}).size);// 2
console.log(Map.of({x:1}, 2, [3], 4).size);// 2

// map
console.log(Immutable.fromJS({key: "value2", key1: "value1"}).count());// 4
// 可以定制条件，来确定大小
console.log(Immutable.fromJS({key: 1, key1: 34}).count((value, key, obj) => {
    return value > 3;
}));// 1 value大于3的有两个

// list
console.log(Immutable.fromJS([1, 2, 5, 6]).count());// 4
// 可以制定条件，来确定 大小
console.log(Immutable.fromJS([1, 2, 5, 6]).count((value, index, array) => {
    return value > 3;
}));// 2 大于3的有两个

Immutable.fromJS([1,2,3,{a:4,b:5}]).has('0'); //true
Immutable.fromJS([1,2,3,{a:4,b:5}]).has('0'); //true
Immutable.fromJS([1,2,3,{a:4,b:5}]).hasIn([3,'b']) //true

Immutable.fromJS([1,2,3,{a:4,b:5}]).includes(2); //true
Immutable.fromJS([1,2,3,{a:4,b:5}]).includes('2'); //false 不包含字符2
Immutable.fromJS([1,2,3,{a:4,b:5}]).includes(5); //false 
Immutable.fromJS([1,2,3,{a:4,b:5}]).includes({a:4,b:5}) //false
Immutable.fromJS([1,2,3,{a:4,b:5}]).includes(Immutable.fromJS({a:4,b:5})) //true

Immutable.fromJS([1,2,3,{a:4,b:5}]).first()//1
Immutable.fromJS([1,2,3,{a:4,b:5}]).last()//{a:4,b:5}

Immutable.fromJS({a:1,b:2,c:{d:3,e:4}}).first() //1
Immutable.fromJS({a:1,b:2,c:{d:3,e:4}}).first() //{d:3,e:4}

/ Map
// 将 key 位置的元素替换为 value
const $obj1 = Map({a: {a1: 34}, b: 2, c: 3, d: 444});
console.log($obj1.set('a', 0).toJS()); // {a: 0, b: 2, c: 3, d: 444}
console.log($obj1.set('e', 99).toJS());  // {a: 1, b: 2, c: 3, d: 444, e: 99}

// List
// 将 index 位置的元素替换为 value，即使索引越界也是安全的, 空位 undefined
const $arr1 = List([1, 2, 3]);
console.log($arr1.set(-1, 0).toJS()); // [1, 2, 0]  注意-1 等效于 $arr1.set($arr1.size + -1, 0)
console.log($arr1.set(4, 0).toJS());  // [ 1, 2, 3, undefined, 0 ]  空位置为了undefined

// Map
console.log(Immutable.fromJS([1, 2, 3, {a: 45, b: 64}]).setIn(['3', 'a'], 1000).toJS());//[1, 2, 3, {a: 1000, b: 64}]

// List
console.log(Immutable.fromJS([1, 2, 3, {a: 45, b: 64}]).setIn(['3', 'a'], 1000).toJS());//[1, 2, 3, {a: 1000, b: 64}]

////List
const list = List([ 'a', 'b', 'c' ])
const result = list.update(2, val => val.toUpperCase())

///Map
const aMap = Map({ key: 'value' })
const newMap = aMap.update('key', value => value + value)

Map({ key: 'value' }).clear()  //Map
List([ 1, 2, 3, 4 ]).clear()   // List

List([ 0, 1, 2, 3, 4 ]).insert(6, 5) //List [ 0, 1, 2, 3, 4, 5 ]
List([ 1, 2, 3, 4 ]).push(5) // List [ 1, 2, 3, 4, 5 ]
List([ 1, 2, 3, 4 ]).pop() // List[ 1, 2, 3 ]
List([ 2, 3, 4]).unshift(1) // List [ 1, 2, 3, 4 ]
List([ 0, 1, 2, 3, 4 ]).shift() // List [ 1, 2, 3, 4 ]

const List = list1.concat(list2)

Map({a:1,b:2}).map(val=>10*val)
//Map{a:10,b:20}